For a long time, I've always remembered to stand on 16 against dealer 10 @ TC of 0 or more. When I have a RC of 0, it's also a TC of 0, so I stand.
However, today I come across this video, starts at 1:50, Collin claims to hit on 16 against 10 at RC of 0, and stand at RC of 1 or more.
https://www.youtube.com/watch?v=E8Tdvgpdbrc
My question is: Is RC of 0 sufficient to stand, or it's better to wait until RC reaches 1?
I tried to figure out the correct answer by consulting the EOR chart on page 515 of BJA3, but I seem to have failed cause there're so many combinations that result in a RC of 0.
Intuitively, I think in average RC of 0 is not sufficient to stand, but I'm not sure.
2=-0.2903
3=-0.8042
4=-1.7279
5=-2.5683
6=1.6446
7=-0.7109
9=0.5524
10=1.1151
m6=-0.0233
Adjustment Factor=51/(52k-n), k is # of decks, n is # of cards removed.
Player 10,2,4 vs Dealer 10 RC=0
(-0.2903-1.7279+1.1151+1.1151)*[51/(312-4)]+(-0.0233)=0.012
A Positive number, RC of 0 is not sufficient to stand.
Player 9,7 vs Dealer 10 Extra 4 is seen RC=0
(0.5524-0.7109+1.1151-1.7279)*[51/(312-4)]+(-0.0233)=-0.151
A negative number, RC of 0 is sufficient to stand.
Player 10,6 vs Dealer 10 Extra 5 is seen RC=0
(1.1151+1.6446+1.1151-2.5683)*[51/(312-4)]+(-0.0233)=0.193
A Positive number, RC of 0 is not sufficient to stand.
Player 10,2,4 vs Dealer 10 Extra 7 is seen RC=0
(1.1151-0.2903-1.7279+1.1151-0.7109)*[51/(312-5)]+(-0.0233)=-0.106
A negative number, RC of 0 is sufficient to stand.
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