Adding AA78mTc side count to High Low

[bjanalyst]

He already said in other posts that he doesn't want to start with a stronger count like a level 2 count system. He just want to stick with level 1 like Hi-lo or KO.

There is no reason to start with a more complicated base count than the simple level one KO count. Using psrc = KO + k*(5m7c) you can derive all kinds of different level counts. For exmaple, brc = KO + (1/2)*(5m7c) where you get a level 3 count with tag values of 1, 1, 1, 1.5, 1, 0.5, 0, 0, -1, -1 for 2, 3, 4, 5, 6, 7, 8, 9, T, Ace respectively all derived from two smple level one counts, KO and 5m7c.

Now consider something more complicated. Consider standing on hard 14 v T which I discussed previously. Stand on hard 14 v T when KO - 1.5*(5m7c) >= crc(7). See attached file. Here the 7's are counted as +2.5, the fives as -0.5 and other ranks as zero or 1. So what count level would this be? This would be a level 5 count and all derived from two simple plus minus counts, KO and 5m7c, using the optimal values of "k" for each situation.
hard 14 v T.jpg