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![Quote](images/misc/quote_icon.png)
Originally Posted by
aceside
I meant to say your calculation of 132.57 is too small. If we consider the real world situation that we only have one match play coupon to use, the chance of winning this particular coupon is 37 times smaller, therefore, the variance with this particular coupon should be be 37 times larger. Is this correct?
No.
![Quote](images/misc/quote_icon.png)
Originally Posted by
aceside
Let us just do these two experiments. #1: I give you only one match play coupon for you to bet 37 times on a Roulette, and your chance of getting an EV of 0.919 is almost zero because this particular coupon will be confiscated after your first use. #2: I give you 37 match play coupons for you to bet each for 37 times on a Roulette, and your chance of getting an EV of 0.919 is likely verified. How do you calculate the EV and variances for these two different cases?
EV and variance have nothing to do with actual outcomes of particular sequences of bets. They are mathematical measures of how much you can expect to win/lose on average and of how far from that expectation you might end up. I have already showed you how to calculate both.
![Quote](images/misc/quote_icon.png)
Originally Posted by
aceside
As I mentioned, I used match play coupons on almost every casino games myself. Trust me.
Based on your fundamental misunderstanding of the basic concepts of the mathematics of games of chance, no one should trust you about anything.
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