I am familiar with Elliot Jacobson's suggestion:
A more reasonable count is a simple “Ten count.” In this count, each of the cards 2, 3, 4, 5, 6, 7, 8, 9 is given the tag +1 and the cards T, J, Q, K are given the tag -2.
Elliot's suggested LLc can be decomposed into the LLc = HL + A789mTc where Ace is zero and 9 is +1. For LL it is just as good as LLc = HL + AA78mTc where 9 is zero and Ace is +1. In either case either the Ace of 9 is counted as+1 and the other as zero. Obviously you want a 2, 3, 4, 5, 6, 7, 8 out of the shoe since if you get one of them you will never get LL. But if you get an Ace you can still get the LL if you get a 9 and if you get a 9 you can still get the LL if you get an Ace. So my original estimate optimal balanced LLc would bethe counts the 2, 3, 4, 5, 6, 7, 8 as +1, Aces and Nines as +1/2 and Tens as-2. But this is a balanced count. Remember I showed that the true count needed for LL betting increases as decks remaining decreases. And you still need to do calculations with the balanced counts. It so happens when you use start increasing LL bet when the unbalanced LLc = KO + AA89mTc >= 30 for the sixdeck game, everything is baked into the cake. The increasing LLc true count needed as dr decreases is automatically built into this and there is no need to estimate decks remaining or do any calculations. It is extremely easy. Also my actual suggested LLc = KO + (3/4)*(AA89mTc) but I chose to use the simpler LLc= KO + AA89mTc which is almost as good. If you used LLc = KO + (3/4)*(AA89mTc) then the 2, 3, 4, 5, 6, 7 would be +1, the 8's and 9's would be +3/4, the Ten's-1.75 and the Aces +1/2. So LLc = KO + (3/4)*(AA89mTc) would be a better LL count and is still unbalanced so just start increasing LL bet when this LLc>= 30 for six decks. And if you want even a better LL count then keep a side count of Queens of Hearts Played. But all of this is cutting hairs. I just use LLc = KO +AA89mTc and start increasing LL bet when LLc >= 30 for six decks. Very simple,no true count calculations and no decks remaining needs to be estimated.
LLc = KO + 0.75(AA89mTc).jpg
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