Adding AA78mTc side count to High Low

[DSchles]

"But it turns out that if a count has a higher average CC it does not necessarily mean that the sim results of that count will be higher."

No, really?? Shocker!!

Don

[bjanalyst]

"But it turns out that if a count has a higher average CC it does not necessarily mean that the sim results of that count will be higher."

No, really?? Shocker!!

Don

I have to admit that you were correct about average CC and sim results. You have to analyze each CC for each situation individually as an average, especially a straight average, can be misleading.

Attached is a chart for each of the 118 for HL + k1*(AA78mTc) + k2*(5m6c) with HO2 with ASC SORTED by CHANGE in CC.

Now the CC of each of the I18 can be directly compared.

If HL + k1*(AA78mTc) + k2*(5m6c) beat HO2 with ASC for every single I18, then the conclusion would be that HL + k1*(AA78mTc) + k2*(5m6c) beats HO2 with ASC.

The results are that HL + k1*(AA78mTc) + k2*(5m6c) beats HO2 with ASC, as measured by INDIVIDUAL CC, in 14 of the I18, ties once and losses 3 times. The maximum win is 17.2% and the maximum loss is 11.5%. Also note a resounding 16.9% CC increase over HO2 with ASC for the very important hard 16 v T hit/stand. All losses are shown in red.

Gronbog agreed to do sims of HL + k1*(AA78mTc) + k2*(5m6c) and let's see what happens.

If the simulation results turn out to favorable for HL + k18(AA78mTc) + k2*(5m6c) then I can go into more detail on how to use these side counts. With a little practice, it is really very easy to do.

Add 5m6c sorted.jpg

[BJGenius007]

May I ask what CC is?

[bjanalyst]

May I ask what CC is?

Sorry for using acronyms that some people may not know. CC = Correlation Coefficent between the tag values of the (derived) count and the EoR (Effects of Removal).

Attached is CC for hit/stand hard 16 v T for HL + k1*(AA78mTc) + k2*(5m6c) compared to HO2 + k*(Adef). CC of HL + 0.5*(AA78mTc) + 3*(5m6c) is 94.3% and CC of HO2 + Adef is 77.4%.

So it should be clear that for the all important hard 16 v T, HL + 0.5*(AA78mTc) + 3*(5m6c) beats HO2 + Adef

And as I showed in a previous chart CC of HL + k1*(AA78mTc) + k2*(5m6c) beats CC of HO2 + k*(Adef) in 14 of the I18, ties for one and loses for 3.

16 v T using HL, AA78mTc, 5m6c.jpg
16 v T using HO2, Adef.jpg