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low stakes rookie: dividing the RC
What are the differences in win rate when a player divides his/her RC by full, half, or quarter decks in a shoe game?
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Don Schlesinger: Re: dividing the RC
> What are the differences in win rate when a player
> divides his/her RC by full, half, or quarter decks in
> a shoe game?
Not much. Quarter-deck precision (which is what you mean to write) in a shoe game is utterly useless. Half-deck precision (still full decks, not dividing by half-decks) is slightly superior to always full decks, but the difference isn't large.
Don
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Mike H: Re: dividing the RC
> What are the differences in win rate when a player
> divides his/her RC by full, half, or quarter decks in
> a shoe game?
Most count systems calculate true count by dividing the running count by the number of full decks remaining. If there's 2 1/2 decks remaining you can either divide by 3 or for more accuracy divide by 2 1/2 = 5/2 (multiply by 2/5 or .4). You're still dividing by full decks but with half deck precision.
As published, the Zen count calculates true count by dividing by quarter decks remaining while the Mentor count calculates per 2 decks remaining. So with 1 deck remaining Mentor divides by 1/2 or multiplies by 2.
It might help to make a table and convert whatever you would be dividing by into something you can multiply by. So if there's 3 1/2 decks left you know to multiply by .3 etc.
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