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Thread: 7up: When should we surrender against 7?

  1. #1
    7up
    Guest

    7up: When should we surrender against 7?

    We are told ??Never??, because the chance for dealer??s bust is always higher than 25%.

    But this is not the case when the ratio of neutral cards is below 1/13.
    An example:
    Here is some data from Keith Collins:
    dealing from a 6 deck shoe, using a weighted average of all possible subsets relative to Hi-Lo:
    Cards in deck = 52 (Running count = +10, no specific removals) : TC = +10

    p(2) = 5.79879280021777E-2

    p(7) = 7.59376758901768E-2

    p(1) = 9.64494664637162E-2

    p(10) = 3.85797865854865E-1
    Since there are no specific removals -
    p(6) = p(5) = p(4) = p(3) = p(2)
    p(9) = p(8) = p(7)
    p(10) = 4 * p(1)

    This gives the chance of dealer??s bust below 25%

  2. #2
    Don Schlesinger
    Guest

    Don Schlesinger: Re: When should we surrender against 7?

    Hi-Lo indices (you never specified a count) for surrendering against 7 are, according to Wong's "Pro BJ" (approximately):

    16: +12
    15: +10
    14: +16

    But, I'm not comfortable with the index for 16 being higher for that of 15. Maybe someone can sim.

    Don


  3. #3
    LVBear584
    Guest

    LVBear584: Index for 16 higher than 15

    But, I'm not comfortable with the index for 16 being higher for that of 15. Maybe someone can sim.

    Drawing an Ace is more beneficial when you are holding 16 vs. 7 than it is when holding 15 vs. 7.


  4. #4
    7up
    Guest

    7up: Thanks Don! *NM*


  5. #5
    kc
    Guest

    kc: Re: When should we surrender against 7?

    > We are told ??Never??, because the chance for
    > dealer??s bust is always higher than 25%.

    > But this is not the case when the ratio of neutral
    > cards is below 1/13.
    > An example:
    > Here is some data from Keith Collins:
    > dealing from a 6 deck shoe, using a weighted average
    > of all possible subsets relative to Hi-Lo:
    > Cards in deck = 52 (Running count = +10, no specific
    > removals) : TC = +10

    > p(2) = 5.79879280021777E-2

    > p(7) = 7.59376758901768E-2

    > p(1) = 9.64494664637162E-2

    > p(10) = 3.85797865854865E-1
    > Since there are no specific removals -
    > p(6) = p(5) = p(4) = p(3) = p(2)
    > p(9) = p(8) = p(7)
    > p(10) = 4 * p(1)

    > This gives the chance of dealer??s bust below 25%

    I think the case you listed was for a running count of +10 dealt from 6 decks and to a pen where 52 cards remain -
     
    Cards in deck = 52
    p(2) = 5.79879280021777E-2
    p(3) = 5.79879280021777E-2
    p(4) = 5.79879280021777E-2
    p(5) = 5.79879280021777E-2
    p(6) = 5.79879280021777E-2
    p(7) = 7.59376758901767E-2
    p(8) = 7.59376758901767E-2
    p(9) = 7.59376758901767E-2
    p(10) = 3.85797865854865E-1
    p(1) = 9.64494664637162E-2

    .
    This equates approximately to a deck comp of 3,3,3,3,3,4,4,4,20,5. If a 7 is removed and player is assigned a hand of hard 16 his draw win % is .2529 and his stand win % is .2498. So for this one particular run count/pen, the best play would be to hit, followed by surrender, then stand. It is a close decision. Other run count/pens may yield different results. I think the surrender index should be some sort of statistical composite of these.

    BTW, surrender vs 7 will be a pretty rare occurrence.

    kc

  6. #6
    Norm Wattenberger
    Guest

    Norm Wattenberger: Re: When should we surrender against 7?

    For HiLo, 4.5/6, Half-deck resolution, I get:

    vs 7

    16 Hit
    15 +12
    14 +18

  7. #7
    Zenfighter
    Guest

    Zenfighter: Re: Oops

    4 dks , s17 (same as PBJ) and 75% dealt out
     
    Precision: 5 sigma
    Maximum number of pairs of hands at index: 1000 million


    HARD STANDING 16 versus 7 up

    STAND HIT
    12: Adv.:-49.829, SEr 0.093 Adv.:-51.211, SEr 0.088 Dif.: 1.382, SEr 0.120
    13: Adv.:-50.142, SEr 0.124 Adv.:-51.793, SEr 0.118 Dif.: 1.651, SEr 0.161
    14: Adv.:-50.292, SEr 0.151 Adv.:-52.572, SEr 0.142 Dif.: 2.280, SEr 0.195
    15: Adv.:-50.449, SEr 0.199 Adv.:-53.443, SEr 0.186 Dif.: 2.994, SEr 0.257
    16: Adv.:-50.920, SEr 0.251 Adv.:-54.307, SEr 0.234 Dif.: 3.387, SEr 0.324

    Determined surrender index: 13


    HARD STANDING 15 versus 7 up

    STAND HIT
    12: Adv.:-49.592, SEr 0.093 Adv.:-50.560, SEr 0.090 Dif.: 0.968, SEr 0.123
    13: Adv.:-50.117, SEr 0.125 Adv.:-51.386, SEr 0.120 Dif.: 1.270, SEr 0.165
    14: Adv.:-50.184, SEr 0.151 Adv.:-52.537, SEr 0.144 Dif.: 2.353, SEr 0.200
    15: Adv.:-50.375, SEr 0.199 Adv.:-53.594, SEr 0.189 Dif.: 3.219, SEr 0.263

    Determined surrender index: 13


    HARD STANDING 14 versus 7 up

    Determined surrender index: Never Surrender
    Number of pairs of hands played: 131994720




    Well, as you can see here, drawing a card with 16 vs. 7 at TC13 is more expensive than for the other fellow who holds 15 vs. 7.

    Sincerely

    Zenfighter

  8. #8
    Don Schlesinger
    Guest

    Don Schlesinger: Re: When should we surrender against 7?

    > For HiLo, 4.5/6, Half-deck resolution, I get:

    > vs 7

    > 16 Hit
    > 15 +12
    > 14 +18

    Does "hit" imply that it could never be right to surrender? Why would that be? See Zenfighter's post.

    Don

  9. #9
    Don Schlesinger
    Guest

    Don Schlesinger: Damn intuition! :-)

    As I said, my gut told me that something was amiss with Wong's indices.

    Don

  10. #10
    7up
    Guest

    7up: Cards in deck = 208

    Using ??Dealer Probabilities Calculator?? at qfit.com, with Keith Collins?? data:

    Cards in deck = 52 (Running count = +10, no specific removals) : TC = +10
    Dealer??s busing chance= 0.2498

    Cards in deck = 208 (Running count = +40, no specific removals) : TC = +10
    Dealer??s busing chance= 0.2534

    Does it mean anything?

    Some places offer surrender after double.

  11. #11
    Francis Salmon
    Guest

    Francis Salmon: Are you sure?

    I presume you are Keith Collins.You must have realized your results contradict Zenfighter's who gives standing as the better strategy than hitting for both 16 and 15 v 7 in all double-digit TCs.
    I think their is a problem with your method. If I got you right you want to remove the 7 and the two cards of the player's hand only after having established the most probable subset thus removing three more bust cards.This is wrong.When we are facing such a hand, we have already counted the involved cards and there are now 52 cards remaining with an RC of +10.
    If you want to remove the 7,you have to do it from the full 312 cards and the resulting frequency of the 7 in the subset of 52 will be 23/6 =3.8 and not only 3 as with your method.Would that explain the difference?

    Francis Salmon

  12. #12
    Francis Salmon
    Guest

    Francis Salmon: You probably meant

    Vs 7
    Hit 14 always
    Surrender 15 at +18
    Surrender 16 at +12

    This would make more sense.

  13. #13
    Norm Wattenberger
    Guest

    Norm Wattenberger: Depends

    Do you count 8,8v7 separately? CVData looks to see if you are also asking for an 88 index. If you are, it excludes 88 from the general index. If not, it includes 88. I get +12 when you also ask for an 88 index. If you gen a general number for all 16v7, CVData says no surrender. So if you exclude 88, I get:

    16v7 +12 (Split on 88)
    15v7 +12
    14v7 +18

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