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Thread: David M: Card probabilities...can you help?

  1. #1
    David M
    Guest

    David M: Card probabilities...can you help?

    I'd like to know how to solve the following:

    In a four deck game, a four of diamonds is followed by a two of spades.

    After two riffle shuffles, the two of spades still follows the four of diamonds, separated by a few other cards.

    How do I calculate the probability that duplicates of these two cards may appear in the same order somewhere else in the shuffled decks, separated by one, two or three cards?

  2. #2
    qboy
    Guest

    qboy: Re: Card probabilities...can you help?

    The "two riffle shuffles" don't seem to me to have much bearing on the problem, since you are asking whether a duplicate order occurs, not whether the original pair is still there...ROUGHLY, there are 3 other 4D's, followed by a total of 12 cards that could be 2S's (assuming 'a few' means 3 or fewer in between). which would make p= (ROUGHLY) 12/208, or 5%. This ignores a couple things...4D's close to each other for example. True anwser probably +/- 1%...

    > I'd like to know how to solve the following:

    > In a four deck game, a four of diamonds is
    > followed by a two of spades.

    > After two riffle shuffles, the two of spades
    > still follows the four of diamonds,
    > separated by a few other cards.

    > How do I calculate the probability that
    > duplicates of these two cards may appear in
    > the same order somewhere else in the
    > shuffled decks, separated by one, two or
    > three cards?

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