Is an equivalent count that HiOPT II trnaslates to the HiLo count.

[DSchles]

Edited: I think I know where the problem is. In your calculation of the sum of squares of the Hi-Opt II tags, you are not considering the value assigned to the ace (-2) in the side count. Instead of 16, it should be 32.
Now, the square root of 10/32 is 0.6, which, when multiplied by 10, gives +6.

Sincerely,
Cac

Yes, perfect. All is right with the world once again.

Don

[Midnight]

This is interesting. Is this method applicable universally (e.g. to convert from Counting System A to Counting system B just follow these steps) or does this only apply when going from Hi OPT II to Hi Low? Also can it be used to go from a balanced count to an unbalanced one (Hi Low to REKO for instance).

[Cacarulo]

This is interesting. Is this method applicable universally (e.g. to convert from Counting System A to Counting system B just follow these steps) or does this only apply when going from Hi OPT II to Hi Low? Also can it be used to go from a balanced count to an unbalanced one (Hi Low to REKO for instance).

The formula is valid only for systems in TC mode. It doesn't work for systems in RC mode.

Sincerely,
Cac

[DSchles]

This is interesting. Is this method applicable universally (e.g. to convert from Counting System A to Counting system B just follow these steps)

Yes. Balanced counts only. And don't forget the aces!

Don