I'm pretty sure I know the answer here, but I have made false assumptions before, so I want to double check. Sorry for the newbie question.
As I'm getting my game dialed, I want to continue to practice somewhere that I play rated. The casino has a comp program that eliminates the house edge (it actually surpasses it if done right, but lets assume it's a break even game). If we are assuming an actual break even game plus using high-lo (or any legit level one counting system), without mistakes, ANY bet spread would create positive EV however tiny it may be, correct? like 1-2, 1-4, or whatever in a shoe game.
Another way to ask this would be, taking the comps out of the equation, any bet spread no matter how small, is better than no bet spread right? Even if it is only reducing negative EV if not eliminating it. Variance swings aside, just thinking pure EV.
Bookmarks