Hola, soy de República Dominicana, siento escribir en este blog pero veo que es uno de los más actualizados.
Tengo la siguiente preocupación: quiero saber si hay una ventaja real en un juego de black jack con las siguientes reglas:
El crupier se mantiene en los 17, puedo abrir pares hasta 4 veces, puede doblar después de abrir, puede rendirse y el blackjack paga 2 a 1.
¿Cuál sería el borde de la casa?
Help for you-Originally Posted by quimera
https://www.qfit.com/blackjack-odds-calculator.htm
"Don't Cast Your Pearls Before Swine" (Jesus)
Somebody here just calculated this today:
If a blackjack pays 6:5, house gets an advantage of 1.5%.
we can easily extrapolate this to your situation:
if a blackjack pays 2:1, player gets an advantage of 2.5%.
This means your game is great! I would play it all in.
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For the most part, a counter does not have to add and subtract single cards, which is tedious , but counts them in pairs, with lots of (+1, -1) cancellations that can be ignored. For reasons of simplicity, I would choose a count with as much cancellations as possible, at least as a beginnen counter. I have read many books and have the impression that this point is often neglected or hardly treated in literature. For instance, KO has more cancellations than HiLo, and some more complex level 2 or 3 systens must have a very low number of cancellations, making them even more difficult to apply.
Interesting! If blackjack pays 2:1, one powerful counting technique should be to track aces. All other current available systems will be pale. This is easy to find.
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Once a new dealer paid Blackjack 2:1, because it is my homebase, I cannot dramatically increase my bets, but I play as long as I could. After playing for four hours, not one single pit boss found this mistake. I was too tired to continue but I had a great day.
I have another situation in which I understand I can generate additional profitability.
In the casino that I visit most players fold on any hand when the dealer has a 10.9 or 8, many players tend to fold their hand as long as they are below the dealer's card.
when I'm at the table I have the option to buy your hand at half price, so for me it would be 3 to 1 if I win the hand.
What I do not know if it would actually be profitable in most hands for example 14 vs 10,
13 vs 9, etc ..
It would be profitable for any hand where it is incorrect to surrender. The only hands surrendered in a shoe game are 16 vs. 9, T, or Ace, and 15 vs. T. For everything else, if you buy the hand for half, you have positive expectation. Obviously, the higher the e.v. of the hand, the greater your profit, even if the hand has negative e.v. for the basic strategist.
Don
I have been analyzing it and I understand that even if the hand is correct to surrender for example 16 vs 10 if I buy it it would be profitable, because I am going to receive a payment of 3 to 1. I do not know if I am correct because I am not a Gambling expert, I just figured if 16 vs 10 is giving up on an even payout. in a 3 to 1 payment it may be more profitable to ask ..
Don has correctly answered you. The situation of surrender is so rare that most people wouldn’t surrender at all, so they wouldn’t sell their hands to you for half the original bet. Even if he is willing to sell his worst hand of 16 vs 10 to you for half, you barely will make any profit because you are going to lose 3 to 1 of the times.
Last edited by aceside; 12-29-2021 at 07:04 AM.
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