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Thread: Bust Bonus side bet

  1. #40


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    Quote Originally Posted by aceside View Post
    I recently played this bust bonus side bet and have verified this bet is countable.
    Where did you play it and how did you verify it's countable?

  2. #41


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    Quote Originally Posted by aceside View Post
    I recently played this bust bonus side bet and have verified this bet is countable.
    Where did you play it and how did you verify it's countable?

  3. #42


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    Quote Originally Posted by 21forme View Post
    Where did you play it and how did you verify it's countable?
    Let’s wait for K_C and Cacarulo’s results first.

  4. #43


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    Quote Originally Posted by aceside View Post
    <snip>Consider a 6-deck h-17 game. When 208 cards were dealt out (thus 104 cards are remaining) and the HiLo true count is TC=+10, what is the probability of each dealer’s upcard?

    When 208 cards were dealt out (thus 104 cards are remaining) and the HiLo true count is TC=-10, what is the probability of each dealer’s upcard?<snip>
    aceside,

    The first graph of this post answers your queries:

    https://www.blackjacktheforum.com/sh...ncy-vs-HiLo-TC

    Hope this helps!

    Dog Hand

  5. #44


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    Quote Originally Posted by Dog Hand View Post
    aceside,

    The first graph of this post answers your queries:

    https://www.blackjacktheforum.com/sh...ncy-vs-HiLo-TC

    Hope this helps!

    Dog Hand
    Your results are from CVData simulation. They are accurate enough, but I still hope to find a theoretical calculation. Furthermore, I specify the dealing depth at this particular value 208/312 to find out if theoretical values match your simulation results or not.

  6. #45


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    Quote Originally Posted by Dog Hand View Post
    aceside,

    The first graph of this post answers your queries:

    https://www.blackjacktheforum.com/sh...ncy-vs-HiLo-TC

    Hope this helps!

    Dog Hand
    I actually have calculated the first graph. My calculation result for the probability of a dealer's ace up card is P=9.6% (at TC=+10 when 208 cards were dealt out from a 6-deck shoe) matches perfectly to Dog Hand's result in the first graph! Wonderful!

    Note: I revised my numbers.
    Last edited by aceside; 06-05-2022 at 12:01 PM.

  7. #46
    Random number herder Norm's Avatar
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    Well, you made the calculation for one composition. Now make the calculations for all other compositions and create a weighted average.
    "I don't think outside the box; I think of what I can do with the box." - Henri Matisse

  8. #47


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    Quote Originally Posted by aceside View Post
    Did I make some mistake somewhere?
    Between you and doghand, I'll give you 100:1 odds that you made the mistake.

  9. #48


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    Quote Originally Posted by 21forme View Post
    Between you and doghand, I'll give you 100:1 odds that you made the mistake.
    Dog Hand results are correct! I've double checked my math.

  10. #49


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    Quote Originally Posted by aceside View Post
    I actually have calculated your first graph. Here are my results:

    At TC=0, the probability of a dealer's ace up card is P=1/13=7.7%.
    At TC=+10, the probability of a dealer's ace up card is P=8.7%.
    This calculation is really simple. When 208 cards were dealt out from a 6-deck shoe and TC=+10, the most likely (probable) deck composition is (35, 24, 45) for the (low, mid, high) cards. This means the probability of a dealer's ace up card is 45/5/104=8.7%.

    However, you show this number in your first graph as 9.6%. The slope of your curve is two times of mine. Did I make some mistake somewhere?
    aceside,

    One difference is that you are calculating the percentages specifically at 208 cards penetration, while my graphs are a weighted averaged over all penetrations up to 75% (actually, a bit under 234 cards, since the cut card appears during the last round).

    The case you showed as (35, 24, 45) corresponds to 43.27% bigs, but the (small, middle, big) distribution will vary slightly with penetration: for example, if your penetration is 10 (instead of 208), the only possible +10 distribution is (110, 72, 120) or 39.74% bigs, since all 10 cards have to be small. On the other hand, if the penetration is 302, the only possible +10 distribution is (0, 0, 10), or 100% bigs... Hint, bet the MAX! ;-)

    Hope this helps!

    Dog Hand

  11. #50


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    Quote Originally Posted by Dog Hand View Post
    aceside,


    Dog Hand
    I miscalculated the TC in my first version and realized my mistake. Thank you for helping!

  12. #51


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    If 208 cards are randomly dealt and counted from a 6 deck shoe, running count is +10, and no other cards are specifically removed the probabilities of each up card would be p[1] through p[10] below.

    Code:
    Count tags {1,-1,-1,-1,-1,-1,0,0,0,1}
    Specific removals (1 - 10): {0,0,0,0,0,0,0,0,0,0}
    No subgroup (removals) are defined
    Decks: 6 (possible input for cards remaining: 1 to 312)
    Cards remaining before up card (current = 156, no input = no change): 104
    Initial running count (full shoe): 0
    Running count (before up card is dealt, no input defaults to 0): 10
    Computing.....please wait.....
    
    Number of subsets for above conditions: 37
    Prob of running count 10 with above removals from 6 decks: 0.02147
    
    p[1] 0.08657  p[2] 0.06734  p[3] 0.06734  p[4] 0.06734  p[5] 0.06734
    p[6] 0.06734  p[7] 0.07682  p[8] 0.07682  p[9] 0.07682  p[10] 0.34628
    An estimate of dealer probabilities based on dealing from a shoe using those rank probabilities for both dealer standing on and hitting soft 17 are below.

    Code:
    Dealer probabilities - 6 decks dealer stands on soft 17....
    Count tags {1,-1,-1,-1,-1,-1,0,0,0,1}
    Specific removals (1 - 10): {0,0,0,0,0,0,0,0,0,0}
    Subgroup removals: None
    Running count (before up card is dealt): 10   Cards remaining: 104
    
    Up card    17      18      19      20      21      BJ     BUST
       1     0.1125  0.1217  0.1223  0.1243  0.0474  0.3496  0.1222
       2     0.1288  0.1221  0.1267  0.1230  0.1198  0.0000  0.3795
       3     0.1221  0.1196  0.1155  0.1199  0.1165  0.0000  0.4065
       4     0.1205  0.1086  0.1117  0.1093  0.1133  0.0000  0.4366
       5     0.1125  0.1119  0.1081  0.1007  0.1015  0.0000  0.4653
       6     0.1714  0.0951  0.0969  0.0930  0.0909  0.0000  0.4528
       7     0.4002  0.1369  0.0683  0.0705  0.0666  0.0000  0.2574
       8     0.1209  0.3903  0.1295  0.0609  0.0631  0.0000  0.2353
       9     0.1131  0.1027  0.3846  0.1232  0.0546  0.0000  0.2218
      10     0.1062  0.1038  0.1052  0.3677  0.0292  0.0874  0.2004
    
    Overall  0.1394  0.1324  0.1294  0.1944  0.0649  0.0605  0.2790
    
    Press c or C for values conditioned on no dealer BJ, any other key to exit
    
    
    Dealer probabilities - 6 decks dealer hits soft 17....
    Count tags {1,-1,-1,-1,-1,-1,0,0,0,1}
    Specific removals (1 - 10): {0,0,0,0,0,0,0,0,0,0}
    Subgroup removals: None
    Running count (before up card is dealt): 10   Cards remaining: 104
    
    Up card    17      18      19      20      21      BJ     BUST
       1     0.0535  0.1317  0.1315  0.1336  0.0567  0.3496  0.1433
       2     0.1200  0.1237  0.1280  0.1244  0.1212  0.0000  0.3827
       3     0.1149  0.1208  0.1166  0.1209  0.1176  0.0000  0.4092
       4     0.1128  0.1100  0.1128  0.1105  0.1144  0.0000  0.4395
       5     0.1083  0.1126  0.1087  0.1014  0.1022  0.0000  0.4669
       6     0.1174  0.1044  0.1053  0.1015  0.0995  0.0000  0.4719
       7     0.4002  0.1369  0.0683  0.0705  0.0666  0.0000  0.2574
       8     0.1209  0.3903  0.1295  0.0609  0.0631  0.0000  0.2353
       9     0.1131  0.1027  0.3846  0.1232  0.0546  0.0000  0.2218
      10     0.1062  0.1038  0.1052  0.3677  0.0292  0.0874  0.2004
    
    Overall  0.1287  0.1342  0.1310  0.1961  0.0666  0.0605  0.2828
    
    Press c or C for values conditioned on no dealer BJ, any other key to exit
    k_c

  13. #52


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    Quote Originally Posted by k_c View Post
    If 208 cards are randomly dealt and counted from a 6 deck shoe, running count is +10, and no other cards are specifically removed the probabilities of each up card would be p[1] through p[10] below.

    k_c
    This work is done magically! I’ve been waiting for this for a long time. Thank you for your hard work! For the sake of the Bust Bonus side bet, let me focus on the hit-17 game and do a little additional calculation based on your results:

    When the dealer shows an Ace up card, she will peek for blackjack. After this peeking, the dealer bust rate becomes

    0.1433/(1-0.34628)=0.2192.

    When the dealer shows a ten-valued up card, she will peek for blackjack. After this peeking, the dealer bust rate becomes

    0.2004/(1-0.08657)=0.2194.

    These two numbers look good, but there is a tiny math problem here. For example, when the dealer shows an Ace up card, the probability of her having a ten-valued under card is slightly greater than 0.34628 though, and thus the probability of having a blackjack is more. Can you also help with this part of calculation?

    P.S. I thought about this again and realized that it was an overkill to consider this tiny math problem. In the subsequent calculation, we just believe the remaining 104-card deck is an infinite deck with a constant probability of each existing card as you calculated. For this side bet, what really matters is the dealer bust rate after peeking.
    Last edited by aceside; 06-06-2022 at 09:22 AM.

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