Ive often thought about a secondary count to use with hi-lo..It would entail counting the ace at +2 and the 7 and 8 at +1 each vs. tens at -1 each.

Hi-Lo: 11111000-1-1

W/Side-Count: 111111110-2
ins(.9813)

Im sure some work would be involved but it would also be very efficient for 11 12's 13's and 14's..Now just surrender your 15's and 16's