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Thread: What the odds for dealer to get 26 on 3 cards

  1. #1


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    What the odds for dealer to get 26 on 3 cards

    Here at Hawaiian garden casino if dealer get 26 in 3 cards all players that bust push

    what will be the odds for it

    any information will be greatly appreciated

    yossi

  2. #2


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    Quote Originally Posted by abukase7 View Post
    Here at Hawaiian garden casino if dealer get 26 in 3 cards all players that bust push

    what will be the odds for it

    any information will be greatly appreciated

    yossi
    abukase7,

    To get a 3-card 26, the dealer must have a 2-card 16 and then hit with an X. The dealer therefore must have one of these five hands:

    1. X, 6, X
    2. 6, X, X
    3. 9, 7, X
    4. 7, 9, X
    5. 8, 8, X

    The answer depends on the number of decks, which you did not specify, so I'll assume it is a 6D game. I'll also neglect rounds where all the players have BJ, so the dealer needn't complete her hand.

    Probability of 1: (96/312)*(24/311)*(95/310) = 218,880/30,079,920 = 0.00727662

    Probability of 2: (24/312)*(96/311)*(95/310) = 218,880/30,079,920 = 0.00727662 (same as 1, obviously)

    Probability of 3: (24/312)*(24/311)*(96/310) = 55,296/30,079,920 = 0.00183830

    Probability of 4: (24/312)*(24/311)*(96/310) = 55,296/30,079,920 = 0.00183830 (same as 3, obviously)

    Probability of 5: (24/312)*(23/311)*(96/310) = 52,992/30,079,920 = 0.00176171

    Summing, we get the probability of a dealer 3-card 26 as 0.0199915, or 1 in 50.02 rounds.

    Hope this helps!

    Dog Hand

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    What about 2-card 15 and an ace?

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    Quote Originally Posted by Phoebe View Post
    What about 2-card 15 and an ace?
    That is only a 16 and dealer will take another hit. If the dealer gets a 10 then that will be a four card 26.

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    Oups. I only wake up

  6. #6


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    Thank you that helpfull .
    ok it is a 2 deck game 55 cut

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    Abd 6 to 5 if it make any different ones

  8. #8


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    abukase7,

    UPDATE: it's a 2D game. Here are the updated calculations.

    To get a 3-card 26, the dealer must have a 2-card 16 and then hit with an X. The dealer therefore must have one of these five hands:

    1. X, 6, X
    2. 6, X, X
    3. 9, 7, X
    4. 7, 9, X
    5. 8, 8, X

    I'll neglect the rounds where all the players have BJ, so the dealer needn't complete her hand.

    Probability of 1: (32/104)*(8/103)*(31/102) = 7,936/1,092,624 = 0.00726325

    Probability of 2: (8/104)*(32/103)*(31/102) = 7,936/1,092,624 = 0.00726325 (same as 1, obviously)

    Probability of 3: (8/104)*(8/103)*(32/102) = 2,048/1,092,624 = 0.0018744

    Probability of 4: (8/104)*(8/103)*(32/102) = 2,048/1,092,624 = 0.0018744 (same as 3, obviously)

    Probability of 5: (8/104)*(7/103)*(32/102) = 1,792/1,092,624 = 0.0016401

    Summing, we get the probability of a dealer 3-card 26 in a DD game as 0.019915, or 1 in 50.2 rounds, or slightly more often than in a 6D game.

    Hope this helps!

    Dog Hand

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    That perfect answer . Thank you .

  10. #10


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    So how much does it alter house edge?

  11. #11


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    Quote Originally Posted by Dog Hand View Post
    Summing, we get the probability of a dealer 3-card 26 in a DD game as 0.019915, or 1 in 50.2 rounds, or slightly more often than in a 6D game.
    Nope. Slightly less often!

    Don

  12. #12


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    Quote Originally Posted by 21forme View Post
    So how much does it alter house edge?
    First, the player has to bust. The global bust rate for the BS player is about 16%, but that's against all upcards. Since the dealer's upcard can be only 6, 7, 9, or X, you have to figure that the player will bust a little more frequently, standing short only on 6 and hitting to 17 on all the other upcards. Let's just say the player will bust about 20% of the time, or once every five such hands.

    The dealer will bust with 26 once every 50 hands. Together, the bust becomes a push once every 250 hands, which is adding 0.4% to the player's edge.

    Don

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    Quote Originally Posted by DSchles View Post
    First, the player has to bust. The global bust rate for the BS player is about 16%, but that's against all upcards. Since the dealer's upcard can be only 6, 7, 9, or X, you have to figure that the player will bust a little more frequently, standing short only on 6 and hitting to 17 on all the other upcards. Let's just say the player will bust about 20% of the time, or once every five such hands.

    The dealer will bust with 26 once every 50 hands. Together, the bust becomes a push once every 250 hands, which is adding 0.4% to the player's edge.

    Don
    ...and then subtract when the player would've won anyways by beating the dealer's made hand?

    haha...nevermind...dealer doesn't bust in those situations....hit happy hr already....happy Halloween!!!hahaha
    Last edited by Sharky; 10-31-2019 at 01:47 PM.

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