Good strategy?

[ZenMaster_Flash]

both the numerator and denominator change

Let us take an example or two.
The Hi-Lo R.C. is +10 and there are 2 of 6 unseen decks remaining.
R.C. = +10 and T.C. = (precisely) +5.
Now it becomes more likely than 'normal' for extra Aces and Face Cards to be played thus
reducing the R.C. while that number, as it is reduced, is divided by a smaller number of decks
remaining. BUT the delta of the numerator (rate of change) will have a tendency to be dropping
faster than the R.C. is what I was thinking.

Here is an example taken from the aforementioned.
There are 3 players and the cards dealt on the following round are mostly Faces and Aces,
so the R.C. drops to +4. There are 11 cards dealt so now we have +5/1.75 for a T.C. of +2.85
that I floor to +2. The TC was cut in half in one round.

NOW, looking at a more likely reduction in the R.C. so that it drops to +7 we have a computation
of +7/1.75 = (precisely) +4 Did the TC drop in concert with the RC? Yes it did ~ both examples.
Even in the more likely case, the drop-off in TC is anything but precipitous.

I guess that I had been viewing this with less than stellar objectivity. Thanx muchly, Don.

[Norm]

If you take all cases, the TC tends to remain the same, assuming exact TC calculation.

[21forme]

If you take all cases, the TC tends to remain the same, assuming exact TC calculation.

I've never grasped the True Count Theorem, either.

Suppose you deal to the last down to the last card. By definition, the (true and running) count has to approach zero. I know what's coming - after the last card. it's undefined because you can't divide by zero, right? So what about with one card or 5 cards left. Are you saying it remains the same, then becomes undefined?

[Norm]

Yep. TC has no meaning when there are no cards left.

[DSchles]

The concept is a simple one. RC = +10 with five decks left. TC = +2. Now, you deal one deck of the five. The RC drops one-fifth, on average, from +10 to +8. But now, only four decks remain. TC still = +2. On average, it does that all the way to the shuffle.

Bottom line: The tendency is for the TC to remain just where it is, on average.

Don

[Freightman]

Yep. TC has no meaning when there are no cards left.

Which means you can throw index play out the window, because you have something far more valuable - exact info.

[Three]

Suppose you deal to the last down to the last card. By definition, the (true and running) count has to approach zero.

Actually as you approach 0 cards left the TC has a huge magnitude. With one card remaining Hilo TC is either -52 (5 of every 13 times), 0 (3 of every 13 times), or +52 (5 of every 13 times). I don't call that approaching 0. There is no TC when no cards are left because you can't divide by 0 but the RC is 0. Starting to understand TC theorem? LoL

[stopgambling]

Yes this logic is flawed. Wong in at +2 True and don’t hold yourself back from making 6 figures annually if you really have what it takes

maybe a couple years and that's it . lol.

[stopgambling]

True Count Theorem

often not understood well enough . i use a True streak theorem , one tends to win and stay winning or stay losing until everything comes down in a crash ! LOl

[bejammin075]

A deck in motion tends to stay in motion...

[Joe Mama]

And how does this fail to translate into a regressing True Count?

Simple example: Hi-LO count, 5 cards left in deck -- TJQKA, RC=5,TC=52, remove 1 RC=4, TC=52, Remove 1 RC=3, TC=52, and so on. Running count moves towards zero, TC remains the same until RC hits zero.

[DSchles]

Simple example: Hi-LO count, 5 cards left in deck -- TJQKA, RC=5,TC=52, remove 1 RC=4, TC=52, Remove 1 RC=3, TC=52, and so on. Running count moves towards zero, TC remains the same until RC hits zero.

Will you please stop using the phrase "regressing True Count"? There is absolutely no such concept and never has been. I thought I already explained it.

Don

[Midwest Player]

Okay, assume you have a monster running count half way through a 6 deck shoe like RC +18 and TC +6. This is a max bet situation. So if the TC tends to stay the same and not decrease, then you can just quit counting and make max bet for rest of shoe.

I know I have seen TC drop very much on just a couple of hands already and I wouldn't want to max bet until the end.