Originally Posted by
dogman_1234
Using the Insurance Function:
I(T_n, T_s, N) = 2*(T_n/(T_n + T_s + N)) + 5*(T_s/(T_n + T_s + N)) - (N/(T_n + T_s + N))
Where T_n is a non-suited 10, T_s is a suited 10, and N is a non-10 card.
The Expected Value of the above assuming a 6 deck shoe is
I(54, 18, 216) = -0.0625
The EoR for the game can be computed simply by:
D(I(T_n, T_s, N), (T_n, T_s, N)) - I(T_n, T_s, N).
That is, remove a non-10, a non-suited 10, and a suited-10 will prove a simple system for determining +EV games.
I can say that it offers better EV for index play. Insurance is lower than that of the 2-1 offer at other tables.
I should caution that your IC will not be 1.00. I have a feeling it is due to the distribution of suited/non-suited 10's in the deck that will throw the count off of the mean value.
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