the correct formula to compute the true count

[Freightman]

Regarding 6d comments - Agree, or disagree depending on how you do things. For most players, I would agree.
I interpolate right from the start, or close, if you will, resolve by half decks.

There’s that thing on cvcx that allows you to calculate your optimal ramp, and also allows you to do so also by half true counts. You will notice differences in ramping by full versus half true counts.

As an example, the true 1 bucket gives your bet for everything from true 1.0 to true 1.99. Half true counts define from 1.0 to 1.49 and 1.5 to 1.99. RC divided by decks remaining (rounded up) gives you true count resolved by full decks. Now, double your RC, divide by half decks remaining anD voila - a higher degree of accuracy.

Work it through.

Now, Bosox, tell me where that 6d .269 house edge is. I may get so excited, that I might start practicing the FBM ASC.

[Gronbog]

So if I have a quarter of a deck Remaining in a DD game of course they would be shuffling by this time but just for learning purposes and they running count was plus 1 the tc would be 4? If I had a half of a deck remaining Tc would be 2?Is that estimating 1/4 decks? And I think less than one deck Causing the TC to go higher than the RC is throwing me off also

Yes. Looks like you've got it now.

[bigplayer]

After the first round or two of double deck multiply your RC x 6 and insert a decimal point. So +4RC x 6 = 24 = TC 2.4 after you're a bit past halfway thru the first deck multiply by 7. 4x7=28=2.8 when you're close to the 1 deck point but not quite multiply by 9, 4x9=36=3.6. As always floor the fraction or use the rounding method your system demands. Obviously at 1 deck left TC=RC. You can then multiply by 1.2, 1.5, 2, 3, 4, etc.

Sent from my SM-G960U1 using Tapatalk