Originally Posted by
Gronbog
This is where your logic is flawed.
If you take insurance on both hands and the dealer has blackjack, you are correct that the overall result is a push on the non-blackjack hand. However for the blackjack hand, you get paid 2 x half your bet (i.e. even money) and your blackjack hand pushes leaving you with an even money profit on that hand. Exactly the same as if you had just taken even money in the first place.
Now if the dealer does not have blackjack, on your blackjack hand you lose your insurance bet, which is 1/2 of your original bet, but you immediately win 1.5 x your original bet for a profit of (1.5 - .5) = 1 x your original bet. Just as if you had just taken even money.
So, for the blackjack hand, taking even money is exactly the same as taking full insurance.
Bookmarks