I Need Help (In more ways than one!)

[Bodarc]

Slot .jpg

You have 3 slot reels, each containing 20 images. The O's are oranges, the W is wild card and all of the dashes are other symbols.

There are 20 x 20 x 20 combinations or 8,000 combinations.

1. I see how that is done, but what would the formula be?

There are 8 x 1 x 10 or 80 ways of making 3 oranges.

2. I see that but what would the formula be?

There are 1,517 ways of making 2 oranges.

3. I don't see how you get that. Could someone please give me the formula and explain it in simple terms for a simple minded fella?

Thanks for any help!

OR just tell me a book or a site where I can find it.

PSS I am familiar with the permutation and combination formulas. I just don't see how this fits in.

[Stealth]

Do not have your answer but try this link for this and other math questions.

http://www.mathwords.com/index_prob_stats.htm

and then take a look at this

http://wizardofodds.com/games/slots/appendix/4/

[Bodarc]

Great links Stealth. Thanks!

[DSchles]

[QUOTE=Bodarc;169024]Slot .jpg

You have 3 slot reels, each containing 20 images. The O's are oranges, the W is wild card and all of the dashes are other symbols.

There are 20 x 20 x 20 combinations or 8,000 combinations.

1. I see how that is done, but what would the formula be?

Just multiply as you did.

There are 8 x 1 x 10 or 80 ways of making 3 oranges.

2. I see that but what would the formula be?

Just multiply as you did.

There are 1,517 ways of making 2 oranges.

3. I don't see how you get that.

That's because it's the wrong answer. Where did you get it from? You get two oranges by any one of three combinations: O,O,-; -,O,O; or O,-,O. So, you multiply how many of each you have in each of the three configurations and then sum the results:
O,O,- = 8 x 1 x 10 = 80.
-,O,O = 12 x 1 x 10 = 120.
O,-,O = 8 x 19 x 10 = 1,520.
Grand total: 1,720.

Clear?

Don

[BJGenius007]

I got a different answer:

7(orange) x 1 (orange) x 11 (dash&wild/as dash) = 77
7(orange) x 19 (dash) x 10 (orange&wild/as orange) = 1330
12(dash) x 1 (orange) x 10 (orange&wild/as orange) = 120
1 (wild as orange) x 1 (orange) x 10 (dash&wild/as dash) = 10
1 (wild as orange) x 19 (dash) x 10 (orange&wild/as orange) = 190
1 (wild as dash) x 1 (orange) x 10 (orange) = 10

Total = 1737

[Bodarc]

7(orange) x 1 (orange) x 11 (dash&wild/as dash) = 77

1 (wild as orange) x 1 (orange) x 10 (dash&wild/as dash) = 10

1 (wild as dash) x 1 (orange) x 10 (orange) = 10

The wilds as dashes would be counted as three oranges BJGenius.

Don, it is from the 1968 book "Casino Holiday" by Jacques Noir Ph.D. I suppose it was just a misprint in the book. I picked it up for about 4 bucks and 3 bucks shipping. It's worth that just to see the dancing girls on the dust cover. I read entirely too much.

So, this has nothing to do with the formulas for permutations or combinations, you just have to know to multiply this way?

[DSchles]

"So, this has nothing to do with the formulas for permutations or combinations, you just have to know to multiply this way?"

They ARE the formulas for permutations, which simply tell you, in this case, to multiply. Guy has four shirts, three pairs of pants, and five pairs of shoes. How many distinct outfits can he form? Answer: 4 x 3 x 5 = 60.

Don

[Shadowless]

"So, this has nothing to do with the formulas for permutations or combinations, you just have to know to multiply this way?"

They ARE the formulas for permutations, which simply tell you, in this case, to multiply. Guy has four shirts, three pairs of pants, and five pairs of shoes. How many distinct outfits can he form? Answer: 4 x 3 x 5 = 60.

Don

I came up with 300 since he could technically mismatch his shoes to create "distinct" outfits.
Does that answer earn any extra credit?

[Bodarc]

ok I have a lot of study ahead of me for what I'm trying to learn.

Thanks for your help guys!