1 out of 1 members found this post helpful.
Did you find this post helpful?
Yes |
No
Originally Posted by
counter19
Andy Bloch on his video says that after calculating the true count (using Hi-Lo), he subtracts 1, then plays two hands. So if the true count is 5, he will play 2 hands with 4 units on each (he was playing 6 deck in the example). Why does he subtract 1? Also, since he has two hands out there, he really has 8 units at risk. What is the thinking here?
I noticed that his minimum bet is 1/1000 of his bankroll. This sounds like a very conservative calculation for a minimum bet to me, which could be why he can justify risking 8 units in this example.
How the MIT version of Hi-lo works is they convert the running count to true count then they subtract the TC from the "true offset". They defined the true offset as 2 x the players disadvantage. For example, a typical disadvantage for a prefect basic strategy player is .5%. To get the true offset you multiply .5 x 2 = 1. Then he subtract 1 from the TC. If a blackjack game has a player disadvantage of .25% (6 decks, S17, DAS, LS, RSA) then the true offset will be .25 x 2 = .5.
The MIT bet units are determine using the Kelly criterion. They usually set $50 as half of unit and $100 as one unit. They take their entire bankroll and divide into 1/4 of a Kelly. If the true count is 5 their bet basis of fthe Kelly criterion if setting $50 as half of unit will be $400.
Bookmarks