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This is a poor game, but . . .
On average you will get a BJ once in every 22 hands.
A negligible percentage will be pushed.
One of 4 BJ's will be composed of an Ace and a Jack.
That brings us to 1 in 88 hands.
Therefore you gain ½ an average bet that often.
Presuming that you mean that you get 2 to 1 on the Ace / Jack Blackjack.
1/64 (1.6%) of that ~ will be Ace / Jack in Spades.
That is in 1 in every 1,408 hands that you will earn a bonus of 9 units.
Dividing 1 average bet by 1,408 yields 0.06% .
The simplest way to look at this is to estimate the House Edge at 0.60%
and adjust that by "giving back" 1/16 of the value of a Two to One Blackjack payoff.
According to QFIT … Blackjack pays 2:1 - Advantage is 2.25-2.32.
e.v. is 2.30% / 4 That equals 0.58%
Add 0.06% for the Spaded BJ and we can round (up) to .64%
If my figures are correct, that leaves the player with a minuscule "advantage off the top"
This game looks like it is good to play if the penetration is reasonable and tables are uncrowded.
This is just enough to sufficiently improve a shoe game with NDAS, 8 decks. No LS. No RSA.
Question: Dealer does not check for BJ with a 10 UP. Does player "lose all" to a BJ ?
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