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Thread: V-man: Side Count of 7s Questions

  1. #1
    V-man
    Guest

    V-man: Side Count of 7s Questions

    In the 'Best Of Masters' archives, Cacarulo had an excellent post describing the side count of 7s for betting. The formula is:
    (adjusted)TC = (HL_RC*2 + SC_RC)/#DR
    where:
    (adjusted)TC = the adjusted TC for betting at beginning of new round
    HL_RC = the HiLo running count
    SC_RC = side count of 7s with IRC = -4*#decks

    Question 1: Why is running count multiplied by 2? Is it because 7s has a value of about half of a HiLo count?
    Question 2: Plugging in a few values into the formula:
    6 decks, 5 decks remaining, HL_RC=10 (TC=2), #7s seen ranges from 0 .. 13 --> (adj)TC run from -0.8 to 1.8. It looks like we are most of the time overbetting in pure HiLo count (TC=2 in this case)?
    Question 3: If I have some game with certain rules and deck composition in such a way that the effect of removal for the card value 8s to have a ratio of -0.5 (vs +0.59 as in the 7s BJ case), and if I want to follow Cac/7 count, would the following formula work:
    (adj)TC = (RC*2 - #8s)/#DR
    Where:
    RC = running count (balanced count) 8s not accounted.
    #8s = number of 8s seen
    #DR = decks remaining

    Thanks,

  2. #2
    Cacarulo
    Guest

    Cacarulo: Side Count of 7s Answers

    > In the 'Best Of Masters' archives, Cacarulo
    > had an excellent post describing the side
    > count of 7s for betting. The formula is:
    > (adjusted)TC = (HL_RC*2 + SC_RC)/#DR
    > where:
    > (adjusted)TC = the adjusted TC for betting
    > at beginning of new round
    > HL_RC = the HiLo running count
    > SC_RC = side count of 7s with IRC =
    > -4*#decks

    > Question 1: Why is running count multiplied
    > by 2? Is it because 7s has a value of about
    > half of a HiLo count?

    Yes, the idea is to avoid using fractions. When I use the side count of 7s I temporarily change Hi-Lo (-1 1 1 1 1 1 0 0 0 -1) into (-1 1 1 1 1 1 0.5 0 0 -1) which has a better BC. Now, instead of using a count with non-integer tags I simply multiply it by 2 (-2 2 2 2 2 2 1 0 0 -2).
    As you can see, the final system is just 2*Hi-Lo (-2 2 2 2 2 2 0 0 0 -2) + S7 (0 0 0 0 0 0 1 0 0 0). Obviously, since S7 is unbalanced you should start it at the correct IRC (-4*# of decks).

    > Question 2: Plugging in a few values into
    > the formula:
    > 6 decks, 5 decks remaining, HL_RC=10 (TC=2),
    > #7s seen ranges from 0 .. 13 --> (adj)TC
    > run from -0.8 to 1.8. It looks like we are
    > most of the time overbetting in pure HiLo
    > count (TC=2 in this case)?

    That's where the power resides. You're changing a system of BC = 0.969 into a system of BC = 0.984.

    > Question 3: If I have some game with certain
    > rules and deck composition in such a way
    > that the effect of removal for the card
    > value 8s to have a ratio of -0.5 (vs +0.59
    > as in the 7s BJ case), and if I want to
    > follow Cac/7 count, would the following
    > formula work:
    > (adj)TC = (RC*2 - #8s)/#DR
    > Where:
    > RC = running count (balanced count) 8s not
    > accounted.
    > #8s = number of 8s seen
    > #DR = decks remaining

    You can do it only if your adjusted system will have a better BC. Of course, you'll need a significant change.

    Sincerely,
    Cac

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