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Johnny Bravo: Need help with a derivative
Find the slope of the tangent line at the given point.
x=tan(y) The given point is y=pi/3
I keep getting 4 but the answer is 1/4. Could someone please explain the steps to get 1/4?
Thank you,
JB
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Don Schlesinger: Re: Need help with a derivative
> Find the slope of the tangent line at the
> given point.
> x=tan(y) The given point is y=pi/3
> I keep getting 4 but the answer is 1/4.
> Could someone please explain the steps to
> get 1/4?
x = tan y ( Take the derivative of both sides of the equation implicitly)
1 = [(sec y)^2] X ( dy/dx )
dy/dx = 1/(sec y)^2 = (cos y )^2
Evaluated at y = pi/3,
(cos pi/3)^2 = (cos 60 )^2 =( 1/2 )^2 = 1/4
QED
Don
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Johnny Bravo: Thanks *NM*
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Hollywood: Re: Need help with a derivative
> x = tan y ( Take the derivative of both
> sides of the equation implicitly)
> 1 = [(sec y)^2] X ( dy/dx )
> dy/dx = 1/(sec y)^2 = (cos y )^2
> Evaluated at y = pi/3,
> (cos pi/3)^2 = (cos 60 )^2 =( 1/2 )^2 = 1/4
> QED
> Don
When I see a post like this, i'm honored just to know you guys.
Hollywood
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