> Can you point me in the right direction? If
> I wanted to calculate the ten insurance
> break-even true counts for the above count,
> how would I?

It's not that simple. You can find some info on bjmath where Pete Moss developed an algebraic formula for determining indices based on EORs.

> I've never been happy about being an idiot
> and my resignation to this fact has led to
> some lazy habits. I only know, which isn't
> much at all, that insurance has a zero
> expectation at a composition where Q(T) =
> Q(NT)/2, or the NT/T ratio is exactly 2.
> Uncounted ranks should be assumed to consist
> of 1/13 per rank of the total cards in the
> undealt subset. The problem comes in the two
> tags that share the low half. A high count
> can presume an undealt subset that holds
> fewer Fours and Fives among the low cards,
> raising the NT/T ratio.

> I trust departure
> determination algorithms based upon
> simulation of the undealt subset (meaning
> SBA) more than algorithms assuming
> composition of the undealt subset (meaning
> BCA and PBA) for this reason.

You're right here although for insurance, which is a linear function, this is not a problem.

> Is there a quick and dirty approach to this?
> Accuracy two places to the right of the
> decimal is unnecessary. Even one place would
> be overkill; I would be ecstatic with
> accuracy to a fifth, a third or even a half
> of a point.

See Bjmath.

> Thanks in advance and, although I have
> always been impressed with your work, I am
> literally astounded by this development.

You're welcome.

> Congratulations on your insight.

Thank you!

Sincerely,
Cacarulo