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Originally Posted by
JesterCW
Midnight, I’m starting down the rabbit hole of writing simulation code for my own personal understanding and challenge. I have one clarification that I think I understand but want to make sure — whenever I see a letter in your TOR system, that’s an EDI that’s been applied, right?
In the used example, the 8D is throwing me off — is this a negative?
I’ve gone and gotten myself downright confused. If you could be so kinda can you step your way from:
24 23 - 28 16 - 44 12
to
43-8D-42-E
I’m having trouble seeing how it works. Just take the {2,3} grouping of 24. How does this go to 4 using the half deck EDI? Sorry for the confusion.
nvm — got it. Brain hurts today, lol.
Hi Jester, since we use the half deck EDI and we applied it five times (means we subtracted it from our original DC count) you can just sum the EDI five times plus the TOR count that remains after the cancellation (simplification) and you will arrive back at the original Deck composition. I forgot to mention that a letter in the main triplet represents a negative number so in this example D is -4 since d is the fourth letter of the alphabet. See example below, if you sum the EDIs and the numbers of each group you will arrive back at our original:
43 - 8(-4)- 4 2 ............ TOR count after EDI reduction/cancellation
+44 - 4 4 - 8 2 .............EDI applied 1st time
+44 - 4 4 - 8 2 .............EDI applied 2nd time
+44 - 4 4 - 8 2 .............EDI applied 3rd time
+44 - 4 4 - 8 2 .............EDI applied 4th time
+44 - 4 4 - 8 2 .............EDI applied 5th time
24 23 - 28 16 - 44 12 ............ Original DC count
There was another way to check as well. Since we know that our EDI count is 5 based on E and we have the half Deck EDI's all we had to do was multiply each group number in the half deck EDI by the EDI count and then add the TOR count.
half deck EDI 44 -44 -82
EDI count = 5
Multiply EDI count by each half deck EDI value : 4 * 5 4* 5 - 4 * 5 4 * 5 - 8 * 5 2 * 5
Equals 20 20 - 20 20 - 40 20
Now add TOR count + 4 3 - 8 D(-4) - 4 2
Give you original Deck composition 24 23 - 28 16 - 44 22
The EDI reduction is replicating the effects of cancellation in a traditional card counting system. Without it, the numbers in each group would just keep growing until we got to 48 48 - 48 48 - 96 24 at the end of the shoe. This would render the system useless in practice as you can imagine the difficulty that would arise when trying to compute a running count with numbers this large. Now lets calculate the TKO running count for both the TOR count and the original DC count and show that they are equal. This is proof that applying the EDI does not change the running count in an arbitrary system in anyway whatsoever.
{ 2,3}{4,5} {6,7} {8,9} {Tens} {Ace}
TKO K values : 1 1 - 1 0 - (-1) (-1) ........(a)
TOR count: * 4 3 - 8 D(-4) 4 2 ........(b)
Multiply a*b then sum 4 + 3 + 8 + 0 + (-4) + (-2) + 10 ( remember as TKO is unbalanced we have to add in E = 5 (EDI Count) * 2 (unbalance of 2 per half deck for TKO)
RC = 19
{ 2,3}{4,5} {6,7} {8,9} {Tens} {Ace}
TKO K values : 1 1 - 1 0 - (-1) (-1) ........(a)
Original DC count: * 24 23 - 28 16 - 44 2 2 ........(b)
Multiply a*b then sum 24 + 23 + 28 + 0 + (-44) + (-22) + 10 ( remember as TKO is unbalanced we have to add in E = 5 (EDI Count) * 2 (unbalance of 2 per half deck for TKO)
RC = 19
Both running counts are equal in TKO even though the DC numbers in TOR and the original provided with the actual cards removed are very different. Therefore, the K values and EDI’s “map” the TOR count to TKO. If two players were at the same table and one was counting with TKO and the other was using TOR with TKO for betting (TKO K values) and they compared their running counts after each round they would be in exact agreement 100% of the time. This same principle applies to moving from TOR to any card counting system that can be represented by the groupings and unlocks the ability to customize everything for the hand or situation being placed. All you must do is select the k values with the highest correlation to the EORs for the play at hand to maximize the expectation. Also of course you wont be doing all the above in a real game. You would just add the first three numbers in your TOR count and subtract the last two. With practice you get superfast at it. That is not difficult. The difficulty in these DC counts is remembering the count from round to round and that’s where the PAO systems help and are the solution. For the TOR count above my ‘person’ for 43 is Thor there is no ‘action’ because of the D in the middle triplet, when I have a number and letter I represent the number as the number and the letter as an animal in this case a dinosaur because the letter is D, the ‘object’ for 42 in my PAO table is represented by a lifeboat. So my image for this Deck Composition is “THOR and 8 dinosaurs in a lifeboat”. The PAO images are so absurd that you can never forget them even if you leave the table and go get lunch you will still remember the last one hours later. If I was playing and I took a hit to whatever hand I had and got a five I would immediately update the image to 44 which is black widow in my system and the image would the be ‘Black Widow and 8 dinosaurs in a lifeboat’ or 44-8D-42.
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