Originally Posted by

**JohnGalt007**
• If you have T,2 and the dealer has 4, the running count is -1+1+1 = 1, and the true count is 1*(104/101). This happens with probability (C(32,1)C(8,1)C(8,1))/(C(104,2)C(102,1)) = 0.00375.

• If you have 9,3 and the dealer has 4, the running count is 0+1+1 = 2. and the true count is 2*(104/101). This happens with probability (C(8,1)C(8,1)C(8,1))/(C(104,2)C(102,1)) = 0.00094.

• If you have 8,4 and the dealer has 4, the running count is 0+1+1 = 2. and the true count is 2*(104/101). This happens with probability (C(8,1)C(8,1)C(7,1))/(C(104,2)C(102,1)) = 0.00082.

• If you have 7,5 and the dealer has 4, the running count is 0+1+1 = 2. and the true count is 2*(104/101). This happens with probability (C(8,1)C(8,1)C(8,1))/(C(104,2)C(102,1)) = 0.00094.

• If you have 6,6 and the dealer has 4, the running count is 1+1+1 = 3. and the true count is 3*(104/101). This happens with probability (C(8,2)C(8,1))/(C(104,2)C(102,1)) = 0.00041.

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