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# Thread: What Are the Odds of Getting a Blackjack in Spanish 21

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## What Are the Odds of Getting a Blackjack in Spanish 21

I believe in regular blackjack you get a blackjack about once in every 21 hands. Anyone know what the odds are in a Spanish 21 8 deck game?

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With a single deck, the odds are 1 in 27.625. So probably a bit higher then that.

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Originally Posted by Midwest Player
I believe in regular blackjack you get a blackjack about once in every 21 hands. Anyone know what the odds are in a Spanish 21 8 deck game?
Recently I've been researching Spanish 21. Let us consider an infinite Spanish 21 deck,
Card rank: 2, 3, 4, 5, 6, 7, 8, 9, J, Q, K, A
Card Number: 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4

Probability of an ace card: 1/12
Probability of a ten-valued card: 3/12
Probability of a blackjack: (1/12)x(3x12)x2=4.17%

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I used to have an infinite shoe. The landlord complained. Worse yet, it altered the Earth's orbit, among other problems. I got rid of it. Sadly, too late for the dinosaurs.

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I was waiting for some aceside math. MWP - what is the probability that you'll believe his result?

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Originally Posted by 21forme
I was waiting for some aceside math. MWP - what is the probability that you'll believe his result?
I have admitted serval times here, I've never had a math degree, so you must watch my math!

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Originally Posted by aceside
I have admitted serval times here, I've never had a math degree, so you must watch my math!
While I don't like speaking for others, I suspect that most forum members would prefer not to see your math.
What happened to your "read more, post less"?

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Originally Posted by aceside
Recently I've been researching Spanish 21. Let us consider an infinite Spanish 21 deck,
Card rank: 2, 3, 4, 5, 6, 7, 8, 9, J, Q, K, A
Card Number: 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4

Probability of an ace card: 1/12
Probability of a ten-valued card: 3/12
Probability of a blackjack: (1/12)x(3x12)x2=4.17%
Close enough. But the OP asked for eight-deck, so why not show the calculation for that? 2 x (32/384) x 96/383 = 4.1775%.

Don

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Originally Posted by DSchles
Close enough. But the OP asked for eight-deck, so why not show the calculation for that? 2 x (32/384) x 96/383 = 4.1775%.

Don
Can’t resist.
Don, you’re wrong. Dealer gets card before players first card. Assuming dealer doesn’t doesn’t have an ace or face in the hole
2 x (32/384) x 96/382=4.1884

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Originally Posted by Midwest Player
I believe in regular blackjack you get a blackjack about once in every 21 hands. Anyone know what the odds are in a Spanish 21 8 deck game?
For regular BJ in 8D we have:

32/416*128/415*2 = 0.04745
1/0.04745 = 21.07 or once every 21 hands.

For Spanish 21 in 8D we have, as Don well said:

32/384*96/383*2 = 0.04178
1/0.04178 = 23.9375 or once every 24 hands.

Sincerely,
Cac

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