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Thread: playing 3 hands

  1. #1
    Senior Member dalmatian's Avatar
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    playing 3 hands

    Is there a way to sim 3 hands in casino verite? i only see a option of 2 hands in the canned sims.

    it seems that 3 hands wastes about 33% more cards in positive counts but only adds 12% more cash (for same max bets like doing 2x200 vs 3x200).

    I need an approximation of how my bankroll would handle this, and i remember reading somewhere at 2 hands you wanna do 2 x 75% of your optimal 1 hand bet and at 3 hands 3 x 50% of your optimal bet. So let's say my bankroll can handle 1x800$ as max bet. So 2 hands would be 2 x 600 (which on casino verite the ROR is very low) and three hands would then be 3 x 400 ??? Basically, is 1x800 = 2x600 = 3x400 in terms of variance and therefore risk? Is this a good approximation????

    I would like to start doing more advanced betting cover where i do a spread like:

    Negatives: 1x25

    Neutral or slightly negative: 2x50

    +1: 3x100

    +2: 3x200

    +3: 3x300

    +4 and above: 3x400

    How would the above compare to my standard spread (in terms of EV / ROR/ N0 on a 200k bankroll):

    Negatives: 1x25

    Neutral or slightly negative: 2x50

    +1: 2x100

    +2: 2x200

    +3: 2x400

    +4 and above: 2x600


    If the win rates and risk are comparable, i like the 3 hand approach bc a [2x50-3x400, drop to 1x25] spread looks a lot smaller than [2x50-2x600, drop to 1x25]

  2. #2
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    Quote Originally Posted by dalmatian View Post
    and i remember reading somewhere at 2 hands you wanna do 2 x 75% of your optimal 1 hand bet.
    The number should be about 2x67%.

  3. #3
    Random number herder Norm's Avatar
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    Quote Originally Posted by dalmatian View Post
    Is there a way to sim 3 hands in casino verite?
    CVCX: two hands
    CVData: seven hands
    "I don't think outside the box; I think of what I can do with the box." - Henri Matisse

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    Quote Originally Posted by aceside View Post
    The number should be about 2x67%.
    Nope, the number should be 2 x 74% or 3 x 58%. Rounding up 2 x 75% or 3 x 60%.

    Sincerely,
    Cac

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    Aceside math strikes again.

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    "it seems that 3 hands wastes about 33% more cards in positive counts"

    Am I missing something fundamental? I don't really understand that statement...what is meant by waste? How is playing multiple hands wasting a positive count? Is it being suggested that as the count goes positive I should change from 2 hands to 1 hand so that I don't waste any of the positive count?

    In fact, when you think about it...if the shoe is positive don't you want to get in as many hands as you can before the shuffle, so playing multiple hands heads up (I almost always play where I am the only player at my stakes), gives me more hands vs how many cards the dealer would use up if I only play 1 hand.
    Last edited by CEO1; 07-30-2022 at 09:58 AM.

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    See BJA3, pp. 24-26.

    Don

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    Quote Originally Posted by Cacarulo View Post
    Nope, the number should be 2 x 74% or 3 x 58%. Rounding up 2 x 75% or 3 x 60%.

    Sincerely,
    Cac
    Both Cac and 21forme are correct this time again!

  9. #9
    Senior Member dalmatian's Avatar
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    Quote Originally Posted by CEO1 View Post
    "it seems that 3 hands wastes about 33% more cards in positive counts"

    Am I missing something fundamental? I don't really understand that statement...what is meant by waste? How is playing multiple hands wasting a positive count? Is it being suggested that as the count goes positive I should change from 2 hands to 1 hand so that I don't waste any of the positive count?

    In fact, when you think about it...if the shoe is positive don't you want to get in as many hands as you can before the shuffle, so playing multiple hands heads up (I almost always play where I am the only player at my stakes), gives me more hands vs how many cards the dealer would use up if I only play 1 hand.

    So follow me here. There are approximately 2.7 cards depleted on average per hand per round at the table. So there are 2 scenarios we are comparing here. One is playing 2 hands, which plus dealers hand we will have 3 total hands there (for a total of 2.7 X 3 = 8.1 cards depleted per round). The other scenario is playing 3 hands, in which case plus the dealer's hand we have a total of 4 hands there (for a total of 2.7 X 4 = 10.8 cards depleted per round). So per round, 10.8 divided by 8.1 you can see that you are depleting 33% more cards. Now, lets compare how much you bet. To make this simple and see to visualize, lets compare a large number of CARDS that is easily divisible by 3, 4 and 2.7 (3x4x2.7 X lets say 35 =1134).

    So if you're still following me, lets say we are looking at 1134 CARDS coming out and assume you're unit is 200$.

    In playing 2x$200 through these 1134 cards you will see 1134/(average of 8.1 cards per round) = 140 rounds. Since you are betting 2x200 per round that's 140 rounds times 400 = $56,000 bet .

    In playing 3x$200 through these same 1134 cards you will see 1134/(average of 10.8 cards per round) = 105 rounds. Since you are betting 3x200 per round that's 105 rounds times 600 = $63,000 bet .

    So you are betting 63000/56000= 12% more money but using up 10.8/8.1= 33% more cards.

    You quickly see that doing something like 2x200 vs 3x150 in the same example above would result in less total money bet for 3x150 than for 2x200 ([3x150x105=$47,250] vs [2x200x140=$56,000] despite 3x150 being technically more money than 2x200 (but with three hands you see less ROUNDS per the same amount of cards).

  10. #10


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    Only time I'd play 3 hands is if:
    1. You're in a casino with very low table max.
    2. It's the last hand of the shoe in a positive count.

  11. #11


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    Only time I'd play 3 hands is if:
    1. You're in a casino with very low table max.
    2. It's the last hand of the shoe in a positive count.

  12. #12
    Senior Member Gramazeka's Avatar
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    Speaking about the optimal number of boxes, we mean a positive score. With a negative score, of course, it is always better to play only 1 box, or not play at all (wong).

    Some players believe that when increasing the score, it is better to increase the number of boxes than to raise the bet. At first glance, it seems that by doing this, you keep the same MO, while reducing the variance. This opinion is erroneous, because. as the number of boxes increases, the number of hands that can be played with a good score decreases.

    The optimal number of boxes if you play alone at the table is 1 or 2 boxes.
    If 1 outside box is playing at the table, it is best to bet on 2 boxes.
    If 2 extraneous boxes are playing at the table, it is best to bet on 3 boxes.
    If there are 3 outside boxes playing at the table, it is best to bet on 4 boxes.
    If the number of extraneous boxes at the table is not constant with a high positive count, it is best to take all the free boxes.

    The optimal number of boxes does not depend on the positive count level.

    The situation changes at the end of the shuffle if you know that a scoring card is about to come out. In such a situation, it is best to bet on the maximum possible number of boxes (while reducing the bet) in order to draw as many cards from the deck as possible. It is recommended to use this technique for players who have a good eye. Otherwise, there will be more harm than good.

    Sometimes you have to face a situation when the maximum table does not allow you to make optimal bets. In this case, instead of increasing the stakes, you have to increase the number of boxes. The effectiveness of the game is reduced.
    Last edited by Gramazeka; 07-31-2022 at 07:35 PM.
    "Don't Cast Your Pearls Before Swine" (Jesus)

  13. #13
    Senior Member dalmatian's Avatar
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    Quote Originally Posted by Gramazeka View Post
    Speaking about the optimal number of boxes, we mean a positive score. With a negative score, of course, it is always better to play only 1 box, or not play at all (wong).

    Some players believe that when increasing the score, it is better to increase the number of boxes than to raise the bet. At first glance, it seems that by doing this, you keep the same MO, while reducing the variance. This opinion is erroneous, because. as the number of boxes increases, the number of hands that can be played with a good score decreases.

    The optimal number of boxes if you play alone at the table is 1 or 2 boxes.
    If 1 outside box is playing at the table, it is best to bet on 2 boxes.
    If 2 extraneous boxes are playing at the table, it is best to bet on 3 boxes.
    If there are 3 outside boxes playing at the table, it is best to bet on 4 boxes.
    If the number of extraneous boxes at the table is not constant with a high positive score, it is best to take all the free boxes.

    The optimal number of boxes does not depend on the positive count level.

    The situation changes at the end of the shuffle if you know that a scoring card is about to come out. In such a situation, it is best to bet on the maximum possible number of boxes (while reducing the bet) in order to draw as many cards from the deck as possible. It is recommended to use this technique for players who have a good eye. Otherwise, there will be more harm than good.

    Sometimes you have to face a situation when the maximum table does not allow you to make optimal bets. In this case, instead of increasing the stakes, you have to increase the number of boxes. The effectiveness of the game is reduced.
    @Gramazeka - you claim to not cast pearls before swine, but you always break this!!

    very nicely written.

    The main reason I am thinking of doing 3 hands is not for SCORE reasons but rather to "look like a smaller spread" at casinos where it is no longer tolerated my 2x600 spread (which at this point is most casinos).

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