# Thread: di/score/n0 for a side bet

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## di/score/n0 for a side bet

From what I have gathered these formulas are correct..

di = 100/(ev/100)*(sd/100)
score = di^2
n0 = var/ev^2 .. (let it be n01)

Since the n01 is calculated based on the ev for the frequency of the bet, would the play-all n0 (let is be n02) then be the total rounds you would need to play to reach that frequency?

n02 = n01 + (n01 * ((1-frequency)/frequency))

Or would it be calculated differently?

Buster BJ sample pictured below ..Attachment 4524  Reply With Quote

2. Did you find this post helpful? Yes | No Originally Posted by Super Natural From what I have gathered these formulas are correct..

di = 100/(ev/100)*(sd/100)
score = di^2
n0 = var/ev^2 .. (let it be n01)

Since the n01 is calculated based on the ev for the frequency of the bet, would the play-all n0 (let is be n02) then be the total rounds you would need to play to reach that frequency?

n02 = n01 + (n01 * ((1-frequency)/frequency))

Or would it be calculated differently?

Buster BJ sample pictured below ..Attachment 4524

Looks a little over-complicated to me. You have the e.v./100 as .70437 and the s.d./100 as 9.9321. So the per-hand values are e.v. = 0.0070437 and s.d. = 0.99321. So, the N0 is simply (0.99321)^2/(0.0070437^2) = 19,888. Q.E.D., no?

Don  Reply With Quote

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Ah thanks Don - I should have figured not to use the first n01 to calc n02.  Reply With Quote

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