Double deck,hi-opt2 with ASC, flooring method and quarter deck resolution.Running count is 6 after seeing exactly 7 or 8 cards without ace in the first round. Whats the correct betting true count now?
TC = (RC + (ASC)) / (104 - 7); ASC = 2 * ((-13 * A + nA) / 13 = 2 * (-13 * 0 + 7) / 13 = 14/13
TC = (6 + (14/13)) / ((104 - 7) / 52)
TC = (7 + 1/13) / (97/ 52)
TC = (85/13) / (97 / 52)
TC = (85 / 97) * (52 / 13)
TC = (0.8763) * 4 = 3.5052
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NOW: for the simple explanation:
TC = (6 + 0*2) / (7.5/4)
TC = 6 * 4 / 7.5 = 3.2 approx.
Basically, you have about a 3 to 3.5 HOII TC.
If you want to include the half extra point from the lack of Aces drawn for the first 1/8 of a deck:
TC = (6 + .5*2) / (7.5/4)
TC = 7 * 4 / 7/5 = 3.73
So, about 3.5
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Not familiar with flooring. What do you mean by that? The TC? RC? The deck resolution?
For single deck and double deck, consider only thinking in terms of 1/4 decks only. Don't sweat how many exact cards have been drawn! Stress over a few floating point values is not going to cost you much in terms of EV.
Think of it this way: Remember that DD has 2 SD's in it. Since we are concerned about 1/4 deck resolution, split the SD into 4 parts and times by 2 for DD. We are working with 8 sections now. Your RC is now going to be the ratio of each available DD section over each SD section. That is:
8/4 7/4 6/4 5/4 4/4 3/4 2/4 1/4...
You get the idea.
For the Ace Side Count: For each DD section drawn add 1 to the ASC. To compute the betting RC using the ASC: take the current ASC, times it by 2, add it to your current RC. That is your adjusted RC for HOII.
Examples:
8/4 sections still available, no Aces drawn. ASC is 0
7/4 sections still available, no Aces drawn. ASC is 1
7/4 sections still available, 2 Aces drawn. ASC is -1 or m1.
To compute the "whole enchilada": assume a HOII RC of 3
8/4 sections still available, no Aces drawn. ASC is 0. ATC = 3 + 0*2 / 8/4 = 3 * 4/8 = 1.5
7/4 sections still available, no Aces drawn. ASC is 1. ATC = 3 + 1*2 / 7/4 = 5 * 4/7 = ~3
7/4 sections still available, 2 Aces drawn. ASC is -1 or m1. ATC = 3 + (-1)*2 / 7/4 = 1 * 4/7 = ~0
At first it seems complex. After about a few weeks of practice, you should be able to compute the Actual True Count with ease.
Hope this helps!
I know how to calculate TC. I'm just a bit confused about how many decks left after seeing 6,7,8 and 9 cards in the first round.Normally I'm just very conservative and floor everything.So I start thinking there are 1.75 decks left after seeing 8 or more cards in the first round and make some ace adjustment to my betting running count next round.Originally Posted by dogman_1234
Forget accounting for some measly 7 or 8 cards! Only focus on 13 card chunks at a time. You only need to worry about:
8/4
7/4
6/4
...
you get the picture. As I stated in my previous post: Don't sweat over such precision. You will only lose a few sig figs in EV by using the 13-card chunks method. Forget accounting for every single card! Not worth it in my opinion.
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