The number of atoms in the known universe is on the order of 10**80.
Was just thinking about that.....
The number of atoms in the known universe is on the order of 10**80.
Was just thinking about that.....
Last edited by BigJer; 02-22-2015 at 07:57 AM. Reason: Edited for correctness.
My Ability in Blackjack is a Gift from God!!
Last edited by BigJer; 02-22-2015 at 09:03 AM.
My Ability in Blackjack is a Gift from God!!
According to http://gizmodo.com/there-are-more-wa...ato-1553612843 there are more ways to shuffle one deck than there are atoms on earth.
My Ability in Blackjack is a Gift from God!!
The first commenter stated: "I just threw up in my brain." That about sums it up. laugh1.gif
Last edited by Aslan; 02-22-2015 at 10:57 AM.
Aslan 11/1/90 - 6/15/10 Stormy 1/22/95 - 8/23/10... “Life’s most urgent question is: what are you doing for others?” — Martin Luther King, Jr.
"Equivalent for blackjack" is different than what I was thinking.
In a 6 pack deck, there will be 6 Queens of Hearts. Ordinarily, I don't care which of those is at position 6 or 79, or 87, or 112, or 221, or 278, but some calculations would count all the orderings where it's just which QH lands in which of those spots separately (all other cards in exactly the same place/order), and some of the calculations would lump all those arrangements together as 1.
At least blackjack is simpler than Tarot reading, where you're concerned about orientation of a particular card, as well as position in the deck. 78! is a big number, and that's before counting reversals.
Last edited by Dieter; 02-22-2015 at 08:40 PM.
May the cards fall in your favor.
Tthree is right, there are at least two much more reasonable interpretations of "distinct" arrangements of cards in a 6-deck shoe, neither of which yields 312! = 2.1x10^644 different orders. If we buy 6 identical standard packs of 52 cards, and consider all cards to be distinct, *except* for the 6 identical copies of each of the 52 cards in a single standard deck, then there are 312!/(6!)^52 = 5.5x10^495 possible arrangements.
If instead we consider *blackjack* shoes, where neither suits nor 10-valued face cards are distinguishable, then there are 312!/(24!)^9/96! = 1.6x10^280 possible arrangements.
Both of which are still incomprehensibly large numbers. Thoroughly shuffle a 6-deck shoe, and it is effectively certain that no one anywhere, ever, has encountered that particular arrangement of cards (even from the more relaxed "blackjack" perspective).
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